stage 3 Logical Operators ruby

I had a same issue. I note it just in case.

def check_speed(car_speed)
  # write your code here
  if car_speed > 39 && car_speed <= 50
    return "safe"
  end
end

if arg1 (insert logical operator) term1 && arg1 (insert logical operator) term 2
  Do some magical Ruby 1337
end

The goal is to perform some type of action if two terms in a conditional are evaluated to be true. If either condition one or condition two are evaluated to be false, the code inside will not be run.

Your use of the operator is right, but you aren't comparing the right terms. You're calling and checking the method check_speed within your conditional for itself. If your method doesn't return anything, then this doesn't make sense - your method check_speed holds no value so it will never be greater than 39 or less than or equal to 50.

Instead, what you want to check, is the argument passed into your method, and return the the string "safe" if the conditional is satisfied (true).

Example:

def check_speed(param1)
  if param1 > value1 && param1 <= value2
    return "w0w such ruby sweg"
  end
end

Never mind I got it! I was missing the extra "end"! *Facepalm *

Try this:

def check_speed(car_speed)
  if car_speed >= 40 && car_speed <= 50
    return "safe"
  end
end

Guys thank for all your help!

Here is what I understood from explanations:

def check_speed(car_speed)
 if car_speed > 40 && car_speed <= 50
    return "Safe"
  end
end 

The check_speed method isn't producing the correct output. Isn't the value of the method check_speed(car_speed)?

Did you ever figure it out? I'm having the same issue...

Sage sorry for the late response: Here is how I got it to work:

def check_speed(car_speed)
  if car_speed > 39 && car_speed <= 50 
    return "safe"
  end
end

You can see the param1 and the value1 was what was giving me a problem.

Best of luck.