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JavaScript Short Circuit Evaluation

alex nonya
PLUS
alex nonya
Courses Plus Student 9,265 Points
Posted by alex nonya
alex nonya
Courses Plus Student 9,265 Points

Start = 0, doesn't work? why does that evaluate to false?

I'm not following why in the example:

function countToFive(start) {

start = start || 1;

for (var i = start; i <= 5; i +=1) {

console.log(i); } }

you can't call the function with, countToFive(0).

how is start = 0 false?

3 Answers

Addy Grothues
.a{fill-rule:evenodd;}techdegree
Addy Grothues
Full Stack JavaScript Techdegree Student 11,062 Points

alex nonya , it would seem that in JavaScript, 0 will default to being false. There are several other things that will also default to false when you are testing for a boolean value (you can see those here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Boolean).

When you are testing a condition with the or || operator, you are testing for a true/false statement (or a boolean value). As mentioned in these videos, when you are testing conditions with ||, once you hit the first false result, that's what you're returned.

So, when start is 0 || 1, it will be false and never get to the 1.

Hope that helps somewhat!

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

It's the other way 'round. When testing with || (OR), a first false is skipped and the other value is returned. So with "start = 0 || 1" it will always get to the 1.

Addy Grothues
.a{fill-rule:evenodd;}techdegree
Addy Grothues
Full Stack JavaScript Techdegree Student 11,062 Points

Thanks for correcting that, Steven!

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

I'm not sure I understand the question. If you call "countToFive(0)", it will log the numbers 1-5 to the console.

The "start" would get reassigned to 1, since the expression "start || 1; evaluates to 1 when "start" is 0.

Please elaborate a bit more if that's not what you were asking.

alex nonya
PLUS
alex nonya
Courses Plus Student 9,265 Points
alex nonya
alex nonya
Courses Plus Student 9,265 Points

Thank you for helping!

"The "start" would get reassigned to 1, since the expression "start || 1; evaluates to 1 when "start" is 0."

Exactly that.....why would the expression evaluate to 1 when 'start' is 0. if 'start' being assigned 2 doesn't default to 1, why does 0 behave differently? What is different in setting 'start' to 2, and having the function count from 2 to 5, and setting 'start' to -2, and having it count from -2 to 5?

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

When evaluated by the "or" operator, 0 is the only numeric value that is considered "falsey".

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

alex nonya — If that answers the question, you can mark it solved by choosing a "best answer".
And happy coding!