Starting year not changing when changing increment operator

Question

I have the following code:

<?php

$currentYear = date('Y');


for ($year = $currentYear - 100; $year <= $currentYear; ++$year) {
  echo $year . " \n";
}

?>

And the starting year is 1917 (it is 2017 at the time I write this). However I thought the operator ++$year is supposed to increment, and THEN return the value, meaning the starting year should be 1918, right?

Also, when I change the operator order to $year++, the starting date does not change. But I believe it should...

Thank you in advance.

C

Answer 1 · 2017-05-30T00:12:52Z

May 30, 2017 12:12am

<?php
/*Loops work in the order of initialization, condition, statement, and then increment, 
just because, the condition comes in the same first line, it would not have any magical power,
for the increment to come first.*/


//the below is how a for loop works
for ($i = 0 /*(1) initialization*/; $i < 5 /*(2) condition*/; $i++ /*(4)increment*./) {
    // (3) do loop stuff
    /*(3)*/ print($i);
}

/*note -> however you address the increment, in the condition area ++$i, or $ii+, 
the result would be the same*/

//behind the scene this is what it is happening
for ($i = 0; $i < 5; ) {
    // do loop stuff
    print($i);

    $i++;
}

/*however if you want to still start from 2018 to print, you can work it out in the statement area
as below*/



$currentYear = date('Y');


for ($year = $currentYear - 100; $year <= $currentYear; ++$year) {
  echo ++$year . " \n";
}



?>

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Cory Norell

Cory Norell

Starting year not changing when changing increment operator

1 Answer

Antonio De Rose

Antonio De Rose