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Mauro Bonucci
5,953 PointsStatus Server 200
Cant pass this challenge, somethings is wrong, i leave my code above:
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if (xhr.readyState === 4){
xhr.readyState === 200)
}
};
xhr.open('GET', 'sidebar.html');
xhr.send();
3 Answers
Dave McFarland
Treehouse TeacherYou need to check that the readyState is 4 AND that the status is 200. That requires using a conditional statement with an AND operator like this:
if (xhr.readyState === 4 && xhr.status === 200) {
}
Robert Bojor
Courses Plus Student 29,439 PointsHi Mauro,
You have an extra ) right after 200, plus you don't set the readyState to 200, no point for that. Check the code below
var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
if (xhr.readyState === 4){ /* Do whatever logic is needed */ }
};
xhr.open('GET', 'sidebar.html');
xhr.send();
Mauro Bonucci
5,953 PointsYour right :-S, thanks Robert