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![Anshul Laikar](https://secure.gravatar.com/avatar/90649bfb03754a4ec6ece4dcf6b269c4?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Anshul Laikar
4,428 PointsString comparison issue
try: quantity_tickets= int(input("How many tickets do you want?")) if quantity_tickets>tickets_remaining: raise ValueError("We do not have that many tickets available") except ValueError as ve: if ve=="We do not have that many tickets available": print(ve) else: print("Please enter a number")
Here is my code. Even if the "We do not have that many tickets available" error is raised, it always ends up printing the "Please enter a number" part. Why is this?
1 Answer
![Jeff Muday](https://uploads.teamtreehouse.com/production/profile-photos/5900142/micro_jeff_face.jpg)
Jeff Muday
Treehouse Moderator 28,718 PointsI have fallen into this trap before! We declared "ve" to be an "Exception" object. This means we can't treat it as a string unless we explicity cast it back to a string type or use ve.message to check the string.
see below:
tickets_remaining = 2
try:
quantity_tickets= int(input("How many tickets do you want?"))
if quantity_tickets>tickets_remaining:
raise ValueError("We do not have that many tickets available")
except ValueError as ve:
# see below where we cast ve to a str object
if str(ve)=="We do not have that many tickets available":
print(str(ve))
else:
print("Please enter a number")
Anshul Laikar
4,428 PointsAnshul Laikar
4,428 PointsThank you so much :)