String Factory Challenge

Let's test unpacking dictionaries in keyword arguments. You've used the string .format() method before to fill in blank placeholders. If you give the placeholder a name, though, like in template below, you fill it in through keyword arguments to .format(), like this: template.format(name="Kenneth", food="tacos") Write a function named string_factory that accepts a list of dictionaries as an argument. Return a new list of strings made by using ** for each dictionary in the list and the template string provided

I'm stuck and have gone through the forum and still can't figure out what I'm doing wrong.

dicts = [
    {'name': 'Michelangelo',
     'food': 'PIZZA'},
    {'name': 'Garfield',
     'food': 'lasanga'},
    {'name': 'Walter',
     'food': 'pancakes'},
    {'name': 'Galactus',
     'food': 'worlds'}
]

string = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(dicts, string):
    string_list = []
    for dict in dicts:
        string_list.append(string.format(**dict))
    return string_list

The error message I keep getting, regardless of how I change it (which has been far too many times now) is: Bummer! string_factory() missing 1 required positional argument: 'string'