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# String Format

in the `{:03.2f}` what does the 03 do? I receive the same result with just `{:0.2f}`

MOD

`{:03.2f}` says "three or more total digits, two digits after the period. Since a float will always have at least one digit in front of the period, `{:03.2f}`, `{:02.2f}`, `{:01.2f}`, and `{:0.2f}` are all equivalent.

Edit: corrected answer based on James Shi's comment.

Technically this is wrong. The 3 means at least 3 characters. The 0 means if there aren't at least 3 characters, pad zeros in front of the number to increase the amount of characters to 3. You only need `{:.2f}`.

James Shi, you are correct! Yes, the "3" does mean "three or more characters".

Part of my point was that with the ".2f" present, the a width value of three or less is equivalent:

```>>> n = 3.14159265358
>>> print("{:03.2f}, {:02.2f}, {:01.2f}, and {:0.2f}".format(n, n, n, n))
3.14, 3.14, 3.14, and 3.14
>>> n = 1023.14159265358
>>> print("{:03.2f}, {:02.2f}, {:01.2f}, and {:0.2f}".format(n, n, n, n))
1023.14, 1023.14, 1023.14, and 1023.14
>>> n = 3.1
>>> print("{:03.2f}, {:02.2f}, {:01.2f}, and {:0.2f}".format(n, n, n, n))
3.10, 3.10, 3.10, and 3.10
```

Thanks for catching this error. I'll update the answer above.