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Python

Posted by alexandracoder0809
alexandracoder0809
2,606 Points

String Formatting with Dictionaries Code Challenge

Hi,

Excuse me for asking again, but I want really to learn what I am doing right and wrong: Here is my code:http://pastie.org/private/dqrab8spjxeofjxz2a

And it gives me that error message:

 new=string.format(**dicts)
TypeError: format() argument after ** must be a mapping, not list

What I am doing wrong here? Am I on the right way for the soloution?

P.S. Is it "normal" that I ask more question in these sections than in the Basics because I find myself struggling harder as further I get. I need some cheering up:)

Thanks in Advance, Alexandra

dicts = [
    {'name': 'Michelangelo',
     'food': 'PIZZA'},
    {'name': 'Garfield',
     'food': 'lasanga'},
    {'name': 'Walter',
     'food': 'pancakes'},
    {'name': 'Galactus',
     'food': 'worlds'}
]

string = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(dicts, string):
    liste1=[]
    for item in dicts:
        new=string.format(**dicts)
        liste1.append(new)
    return liste1

[MOD: copied code from pastie.org -cf]

7 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,468 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,468 Points

Your original code does not use the item loop variable. Replace **dicts with **item as the format() argument.

Avi Tsipshtein
Avi Tsipshtein
7,461 Points
Avi Tsipshtein
Avi Tsipshtein
7,461 Points

This bit of code worked for me:

dicts = [
    {'name': 'Michelangelo',
     'food': 'PIZZA'},
    {'name': 'Garfield',
     'food': 'lasanga'},
    {'name': 'Walter',
     'food': 'pancakes'},
    {'name': 'Galactus',
     'food': 'worlds'}
]

string = "Hi, I'm {name} and I love to eat {food}!"


def string_factory(dicts, string):
    new_list = []
    for key in dicts:
        new_item = string.format(**key)
        print(new_item)
        new_list.append(new_item)
    return new_list
    print(new_list)

string_factory(dicts, string)
Cindy Lea
PLUS
Cindy Lea
Courses Plus Student 6,497 Points
Cindy Lea
Cindy Lea
Courses Plus Student 6,497 Points

Try def string_factory(*dicts, string):

alexandracoder0809
alexandracoder0809
2,606 Points
alexandracoder0809
alexandracoder0809
2,606 Points

It doesn't work. Now it says: string_factory() missing 1 required keyword-only argument: 'string'

What should I do?

alexandracoder0809
alexandracoder0809
2,606 Points
alexandracoder0809
alexandracoder0809
2,606 Points

I have changed it but it doesn't work: See here: http://pastie.org/private/1ggbmohjlxpit1piymeig

alexandracoder0809
alexandracoder0809
2,606 Points
alexandracoder0809
alexandracoder0809
2,606 Points

Thanks. It helped a lot.

alexandracoder0809
alexandracoder0809
2,606 Points
alexandracoder0809
alexandracoder0809
2,606 Points

Thanks for your help.