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Python Regular Expressions in Python Introduction to Regular Expressions Escapes

Posted by Sam Frampton
Sam Frampton
3,796 Points

String is not callable

Running a function name that takes a string as an argument. I get a response string is not callable. Don't understand why.

escapes.py 
import re

first_number = '25namestest'
print(re.search(r'/d','first_number'))

2 Answers

Alexander Davison
Alexander Davison
65,468 Points
Alexander Davison
Alexander Davison
65,468 Points

Defining a variable isn't quite what the challenge is asking for.

Try defining a function instead. Also note that you used a forward slash / instead of a backslash \, and that you surrounded first_number in quotes.

Good luck!

Sam Frampton
Sam Frampton
3,796 Points

Thanks for the advice: It's late here in the UK and I know I am making a stupid mistake but here is where I am stuck at and I seem to be returning the incorrect answer.

import re

def first_number(): string = '12test' return string

print(re.search(r'\d', 'first_number'))

= 'bummer incorrect answer'

Sam Frampton
Sam Frampton
3,796 Points
Sam Frampton
Sam Frampton
3,796 Points 
import re

def first_number(string):
    return re.search(r"\d", string)

Here I found the solution thanks for help