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manoj Singireddy
1,762 Pointsstruck here need help string firstName="Naaz"; console.printf("%s",firstName);
Help
string firstName="Naaz";
console.printf("%s",firstName);
2 Answers
A Y
1,761 PointsManoj,
You have a very small bug in your code: string firstName="Naaz"; console.printf("%s",firstName); (((You have declared the firstName as string instead of String and Java is a case sensitive language means the letters upper case and/or lower case matter and considered errors))) Please try: (((String firstName = "Naaz"; console.printf("%s",firstName);))) and it will work.
Regards, Amir
Jason Anders
Treehouse Moderator 145,858 PointsHey there,
If you're on Task 1, then you shouldn't have that second line... the instructions did not ask for that. However, you have a syntax error in line 1. String type needs to have an upper-case "S" (other than that the syntax is correct 
If you're on Task 2, then I'm not sure what you changed String to string, but the second line is not producing the string that the instructions are asking for. Instructions are very strict and need to be followed exactly, so you just need to output the exact string the instructions are asking for.
Keep Coding! :)
