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Python Python Basics (2015) Letter Game App Even or Odd Loop

Struggling to get While loop to work on this one

I'm struggling to get the while loop to work on this code challenge. When I run the code without the while loop, it work fine and tells me if the random number is even or odd. When I add my while loop structure, the program does nothing. Can anyone point me the right direction here?

import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start is True:

    num = random.randint(1, 99)

    if even_odd(num) is True:
        print("{} is even".format(num))
        print("{} is odd".format(num))

    start -= 1

1 Answer

Steven Parker
Steven Parker
218,812 Points

In Python, "is" is an identity comparison. It only matches if both sides refer to the same thing (not just have the same value).

An equality comparison is the double equal sign operator ("=="). But you don't need that here, since "start" is a number it will never be equal to "True" (a boolean).

You can test a value for "truthiness" just by naming it:

while start:

Similarly, you can test the result of calling "even_odd" directly also.

That helps, thanks!