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Python Python Collections (Retired) Dictionaries Teacher Stats

stuck at teacher stats 3 of 4

Maybe im just slow but these teacher stats exercises are pretty hard.

what is the solution to this?

teachers.py
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(my_dict):
  max_count = 0
  teacher = ""                       # teacher variable holds the name of teacher with most courses
  for i in my_dict:
    if len(my_dict[i]) > max_count:  # if the current teacher has more courses than max_count
      max_count = len(my_dict[i])    # reassign the max_count
      teacher = i                    # reassign the name of this teacher to teacher variable
  return teacher


def num_teachers(my_dict):
  count = 0
  for i in my_dict:
    count += 1
  return count  

def stats(my_dict):
  new_word = []
  for key in my_dict:
    new_words = "{}, {}".format(key, len(my_dict[key])) 
  return new_words.append(new_word)

3 Answers

Karthik Mohandas Bangera
Karthik Mohandas Bangera
2,519 Points

Oh sorry i did not look at that..u don't need that statement, so it should be:

def stats(my_dict):
  teacher_list = []
  for i in my_dict:
    count = len(my_dict[i])    
    teacher = i
    teacher_list.append([teacher,count])
  return teacher_list  

i was wondering what it was for I was like. whaaaaat thank you very much

Karthik Mohandas Bangera
Karthik Mohandas Bangera
2,519 Points
def stats(my_dict):
  teacher_list = []
  for i in my_dict:
    if len(my_dict[i]): 
      count = len(my_dict[i])    
      teacher = i
      teacher_list.append([teacher,count])
  return teacher_list  

i don't get the " if len(my_dict[i]):" what does this do?

Nathan McElwain
Nathan McElwain
4,575 Points

That solution seems a bit overly complicated.... try this:

def stats(n):
    tStats = []
    z = n.items()
    for x, y in z:
      tStats.append([x, len(y)])
    return tStats