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Melissa Bai
5,597 PointsStuck in the challenge: Create a function named most_classes that takes a dictionary of teachers and returns the teacher
Don't understand the Bummer: where's 'most.classes()'
# The dictionary will be something like:
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
teachers = {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
def most_classes(teachers):
max_count = ''
classes = teachers[classkey]
for classes in teachers.values():
if len(classes) > max_count:
max_count = len(classes)
return classkey
print most_classes
2 Answers
Dan Johnson
40,532 PointsYou're using the variable classkey before it's defined which is likely why it can't call/find most_classes.
As for the function, the challenge expects the name of the teacher to be returned. What you can do is iterate through both the key and values and update the leading teacher just like you're doing with the class count, then return the leading teacher at the end.
Abenezer Mamo
5,821 PointsThis is my solution to this problem. It's quite simple to understand and it's efficient.
def most_classes(my_dict):
teachers_list = {}
for teacher in my_dict:
teachers_list[teacher] = len(my_dict[teacher])
return max(teachers_list, key=teachers_list.get)