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baderbouta
7,804 PointsStuck, I've checked everything and It's still not working.
Heya'.
I can't seem to wrap my head around to why this is not working? Can anyone please help me with what the heck is going wrong in this code?
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<link href='http://fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'>
<link rel="stylesheet" href="css/main.css">
<title>AJAX with JavaScript</title>
<script>
// Step 1 // - Create XMLHTTP Request object.
var xhr = new XMLHttpRequest();
// Step 2 // - Create callback function.
//this is the code that is going to run when the server respons to your request.
xhr.onreadystatechange = function () {
if (xhr.readyState === 4) {
document.getElementById('ajax').innerHTML = xhr.responseText;
}
};
// Step 3 // - Open a request.
xhr.open('GET', 'sidebar.html');
//Step 4 // - Send Request
xhr.send();
</script>
</head>
<body>
<div class="grid-container centered">
<div class="grid-100">
<div class="contained">
<div class="grid-100">
<h1>Bring on the AJAX</h1>
<ul id="ajax">
</ul>
</div>
</div>
</div>
</div>
</body>
</html>
1 Answer

Sean T. Unwin
28,686 PointsMissing the button that when pressed calls the the function which xhr.send();
is wrapped in. The function is missing as well.
Check the video from the 9:50 mark.

baderbouta
7,804 PointsFixed it thanks!
Adam Beer
11,314 PointsAdam Beer
11,314 PointsThis is looks good. Maybe you don't saved the file before check