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Subi Sundaram
260 PointsStuck on Array size & length challenge
This is what I've got float real_numbers [] = {1, 2, 3, 4, 5 }; printf("Array real_numbers is %ld. bytes\n", sizeof(real_numbers)/sizeof(float));
and it says its not correct
2 Answers
Jason Anello
Courses Plus Student 94,610 PointsAre you on task 2?
For task 1 you don't have to initialize the array with values but it doesn't hurt. You can pass with float real_numbers[5]. You are simply declaring an array to have room for 5 floats.
For task 2, they want to know the size of the array. So that's sizeof(real_numbers). That gives you the total size of the array. Which is how much space 5 floats would take up.
Subi Sundaram
260 PointsI did initialize task 1 with values but after shortened it I was able to pass task too... although my previous statement ran fine in xcode....