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Python Dates and Times in Python (2014) Let's Build a Timed Quiz App Harder Time Machine

Jackson Porter
Jackson Porter
2,160 Points
Posted by Jackson Porter
Jackson Porter
2,160 Points

Stuck on challenge

I'm just wondering what I'm doing wrong here.

time_machine.py 
import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
def time_machine(inte, stri):
    s = stri
    if s == "year":
        return starter + datetime.timedelta(vars()[s] = inte * 365)
    else:
        return starter + datetime.timedelta(vars()[s] = inte)


## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

1 Answer

Travis Alstrand
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.a{fill-rule:evenodd;}techdegree seal-36
Travis Alstrand
Data Analysis Techdegree Graduate 45,984 Points
Travis Alstrand
.a{fill-rule:evenodd;}techdegree seal-36
Travis Alstrand
Data Analysis Techdegree Graduate 45,984 Points

Hey Jackson Porter ! :wave:

You're very close! We can even shorten it down further here as well. I believe the issue is the string we're checking on and the vars()[] which I'm personally not familiar with.

First, we need to be checking for the string of "years" (plural) instead of "year". If it is "year", we can just re-assign the s variable's value to "days". Then we can re-assign the inte variable's value to inte = inte * 365 or inte *=365.

Then outside of that if, we can utilize the ** unpacking operator like so...

return starter + datetime.timedelta(**{s: inte})