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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

Posted by taejooncho
taejooncho
Courses Plus Student 3,923 Points

Stuck on code challenge: String Formating with Dictionaries

I am not sure what I am doing wrong. I tried this code on eclipse with return replaced with print on line 20, and I believe that the results are what the task is asking me to do.

When I try to check the work in the treehouse I get this

Bummer! string_factory() missing 1 required positional argument: 'template'

I am not sure what I am doing wrong. I would really appreciate some guidance.

string_factory.py 
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]
dicts = [
    {'name': 'Kenneth',
     'food': 'tacos'},
    {'name': 'Michelangelo',
     'food': 'PIZZA'},
    {'name': 'Garfield',
     'food': 'lasagna'},
]

template = "Hi, I'm {name} and I love to eat {food}!"

def string_factory(dicts, template):
    list = []
    for item in dicts: 
        list.append(template.format(**item)) 
    return list

string_factory(dicts, template)

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

You are So close! You do not need to pass template as a parameter. It can be referenced directly as a global variable.

Also, it's a good practice to avoid using built-in keywords or types as variable names. list is the built-in type list. It's better to use a variable name that better represents what's contained in the list. "results" or "result" is often used.

taejooncho
taejooncho
Courses Plus Student 3,923 Points

Thank you! I was stuck on this problem for 2 days and finally solved with your help.

If it is not too much to ask, can you explain what the error(positional argument) was saying so that I will be able to fix this in the future?