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PHP Build a Simple PHP Application Integrating with PayPal HTML Forms

Stuck on HTML form

"Next, we need the flavor selected in the dropdown to be submitted to this process.php file. We need to be able to access it in the “flavor” element of the $_POST array, like this: $_POST["flavor"]. What two changes do we need to make to the HTML? (Hint. We need to add two new attributes. The first needs to be added to one existing HTML element, the second needs to be added to a different existing HTML element.)"

What is wronge here?

form.html
<!DOCTYPE html>
<html>
<head>
    <title>Ye Olde Ice Cream Shoppe</title>
</head>
<body>

    <p>Your order has been created. What flavor of ice cream would you like to add to it?</p>

    <form action="process.php" method="POST">

        <label for="flavor">Flavor</label>
        <select id="flavor">
            <option value="">&#8212; Select &#8212;</option>
            <option value="Vanilla">Vanilla</option>
            <option value="Chocolate">Chocolate</option>
            <option value="Strawberry">Strawberry</option>
            <option value="Cookie Dough">Cookie Dough</option>
        </select>

        <input type="submit" value="Update Order">

    </form>

</body>
</html>

1 Answer

geoffrey
geoffrey
28,724 Points
    <form action="process.php" method="post">

        <label for="flavor">Flavor</label>
        <select id="flavor" name="flavor">
            <option value="">&#8212; Select &#8212;</option>
            <option value="Vanilla">Vanilla</option>
            <option value="Chocolate">Chocolate</option>
            <option value="Strawberry">Strawberry</option>
            <option value="Cookie Dough">Cookie Dough</option>
        </select>

        <input type="submit" value="Update Order">

    </form>

As you'll probably notice, there is a missing information in your code, you forgot to add the name attribute on the select element. Without that, PHP won't have the $_POST["flavor"] variable, that's why you need it. Once a selection will be done through the select, the value will be set to that $_POST[$flavor] variable. That's why It's needed.