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Alex Stephens
13,342 PointsStuck on JavaScript slice method
Hi This is my code i'm stuck on this and i'm 9.99% that is right but what i'm my missing any help will be great.
var first = ["The", "quick", "brown", "fox", "jumps"]
var second = ["over", "the", "lazy"];
var saying = first;
var shortSaying = saying.slice(1,3);//Stuck on!!
var saying = first.concat(second).concat("dog");
var shortSaying = saying;
var sayingString = saying;
5 Answers
Ryan Duchene
Courses Plus Student 46,022 PointsIn that case, your code is in the wrong order. You're getting index 1-3 of what's essentially the first variable.
Try this code instead:
var first = ["The", "quick", "brown", "fox", "jumps"]
var second = ["over", "the", "lazy"];
var saying = first.concat( second ).concat( "dog" ); // this line used to be below
var shortSaying = saying.slice( 1, 4 ); // this line used to above
var sayingString = saying;
Also, in this code challenge, there is no need to add any extra lines of code with new variable assignments.
Ryan Duchene
Courses Plus Student 46,022 PointsFirst, I notice that your first statement doesn't have a semicolon at the end. I'm not sure if that's it, but it very well could be. ;)
I'll update this comment after I do some more digging.
EDIT: In this code challenge, there isn't any need to define any new variables. Your "stuck on" line of code is actually great, but you've written it on the wrong line.
Try that and see if it helps.
Alex Stephens
13,342 Pointswell i'm not stuck on the dog i'm stuck on the one that you got to slice the quick brown fox but i'm 9.99% the numbers that are the index ps how do i but my code in as markup ?
Ryan Duchene
Courses Plus Student 46,022 PointsTo make your code markup, wrap it in a couple newlines and three backticks (`). Look at the Markdown Cheatsheet.
Ryan Duchene
Courses Plus Student 46,022 PointsWell, in the case of .slice(), you're close. You see, the .slice() method stops before the index of its second argument.
It's like if I told you to count from 0 to 5, and told you to stop before 5. You'd stop at 4.
This is the same way. It's counting from index 1 (actually the second element) to index 3 (actually the fourth element), but .slice() tells it to stop before index 3. So, to make up for that, you'll need to pass 4 instead.
Alex Stephens
13,342 Pointsso i would have to change it like this
var first = ["The", "quick", "brown", "fox", "jumps"]
var second = ["over", "the", "lazy"];
var saying = first;
var shortSaying = saying.slice(1,4);//would this work because i tried it not long ago and it's saying wrong.
var saying = first.concat(second).concat("dog");
var shortSaying = saying;
var sayingString = saying;
Alex Stephens
13,342 PointsThank you Ryan Duchene for your help :).
Ryan Duchene
Courses Plus Student 46,022 PointsNo problem!
Ryan Duchene
Courses Plus Student 46,022 PointsRyan Duchene
Courses Plus Student 46,022 PointsFor readability: (only whitespace was changed)
(if you want to format your code like I did there, check out the Markdown Cheatsheet)