Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java IO

Carl Clark
Carl Clark
554 Points

Stuck on Question.

Using the console's printf method, display a message that says, "First name: ", followed by the first name that the user has entered.

IO.java
// I have imported java.io.Console for you.  It is a variable called console.

String firstName = console.readLine("firstName");
String lastName = console.readLine("lastName");

                  console.printf("First name");
                  console.printf("%s\n");

1 Answer

Hi Carl,

alright, good effort so far. I can see what you are trying for, and it makes some sense.

However, you need to write your console.printf statement to include the string the instructions show, as well as the placeholder element %s. after the message string is declared, you'll use a comma, and then declare the variable (in this case, firstName) you'd like to display in the %s position.

see the code below.

// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("firstName");
String lastName = console.readLine("lastName");

//Notice how the %s is a placeholder for the variable you will name after the sentence string
console.printf("First name:  %s", firstName);
Carl Clark
Carl Clark
554 Points

Thanks alot! I got it about a hour ago! My friend helped me it makes alot more sense now!