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Java Java Basics Getting Started with Java IO

Carl Clark
Carl Clark
554 Points

Stuck on Question.

Using the console's printf method, display a message that says, "First name: ", followed by the first name that the user has entered.

IO.java
// I have imported java.io.Console for you.  It is a variable called console.

String firstName = console.readLine("firstName");
String lastName = console.readLine("lastName");

                  console.printf("First name");
                  console.printf("%s\n");

1 Answer

Joseph Wasden
Joseph Wasden
20,406 Points

Hi Carl,

alright, good effort so far. I can see what you are trying for, and it makes some sense.

However, you need to write your console.printf statement to include the string the instructions show, as well as the placeholder element %s. after the message string is declared, you'll use a comma, and then declare the variable (in this case, firstName) you'd like to display in the %s position.

see the code below.

// I have imported java.io.Console for you.  It is a variable called console.
String firstName = console.readLine("firstName");
String lastName = console.readLine("lastName");

//Notice how the %s is a placeholder for the variable you will name after the sentence string
console.printf("First name:  %s", firstName);
Carl Clark
Carl Clark
554 Points

Thanks alot! I got it about a hour ago! My friend helped me it makes alot more sense now!