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PHP

Posted by Adrian Pineda
Adrian Pineda
13,778 Points

STUCK ON TASK 5 OF 7 FOR ASSOCIATIVE ARRAYS PART II.

I know this question has been addressed in another forum, but there is so much information all over the place it's kind of hard to follow. So, here goes, can anyone tell me what i'm doing wrong here?

<?php $movie = array(); $movie["title"] = "The Empire Strikes Back"; $movie["year"] = 1980; ?> <h1><?php echo $movie["title"]; ?> (<?php echo $movie["year"]; ?>)</h1> Thanks!

6 Answers

Nicholas Vandenbroeck
Nicholas Vandenbroeck
4,599 Points

Why use multiple <?php tags? Wrap your code into: 

<?php
    //code
?>

You could also concatenate them using

<?php
    echo $movie["title"] . " (" . $movie["year"] . ")";
?>

This outputs "The Empire Strikes Back (1980)"

Dai Phong
Dai Phong
20,395 Points
Dai Phong
Dai Phong
20,395 Points

Try to do like below, it may help you

 $movie = array(

      title => "The Empire Strikes Back",

      year => 1980

 );
Adrian Pineda
Adrian Pineda
13,778 Points
Adrian Pineda
Adrian Pineda
13,778 Points

Thanks guys I got it using Nicholas' code suggestion:

<?php $movie = array(); $movie["title"] = "The Empire Strikes Back"; $movie["year"] = 1980; ?> <h1><?php echo $movie["title"] . " (" . $movie["year"] . ")"; ?></h1>

Nicholas Vandenbroeck
Nicholas Vandenbroeck
4,599 Points
Nicholas Vandenbroeck
Nicholas Vandenbroeck
4,599 Points

You should probably using Dai Phong's method. That is the associative way of doing it.

Adrian Pineda
Adrian Pineda
13,778 Points
Adrian Pineda
Adrian Pineda
13,778 Points

Yeah I actually did it that way too and was having was having problems so I just did it the basic way. That way is better though and I'll definitely use that method when writing code!

Robbie Thomas
Robbie Thomas
31,093 Points
Robbie Thomas
Robbie Thomas
31,093 Points

Try this instead, if you haven't passed it yet:

<?php

$movie = array( "title" => "The Empire Strikes Back", "year" => 1980 )

?>

<h1><?php echo $movie["title"]; ?> (<?php echo $movie["year"]; ?>)</h1>

Gave me green.