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PHP Object-Oriented PHP Basics (Retired) Inheritance, Interfaces, and Exceptions Final Challenge

Oğulcan Girginc
Oğulcan Girginc
24,848 Points
Posted by Oğulcan Girginc
Oğulcan Girginc
24,848 Points

Stuck on the 6th OOP Basics Challenge!

Hi,

Once again, I can't figure out what I am missing! Challenge Task 6 of 7 asks me to:

Add a getInfo method to your Trout class that returns a string containing the common_name, flavor, record_weight, and species properties. For example, on our brook trout it might return "Brook Trout tastes Delicious. The record Brook Trout weighed 14 pounds 8 ounces."

Bummer! Try again!

fish.php 
<?php

class Fish
{
    public $common_name;
    public $flavor;
    public $record_weight;

    function __construct($name, $flavor, $record)
    {
        $this->common_name = $name;
        $this->flavor = $flavor;
        $this->record_weight = $record;
    }

    public function getInfo() 
    {
        $output  = "The {$this->common_name} is an awesome fish. ";
        $output .= "It is very {$this->flavor} when eaten. ";
        $output .= "Currently the world record {$this->common_name} weighed {$this->record_weight}.";
        return $output;
    }
}

class Trout extends Fish
{
  public $species;

    function __construct($name, $flavor, $record, $species)
    {
        parent::__construct($name, $flavor, $record);
          $this->species = $species;
    }

    public function getInfo()
    {
        return  $this->species . " " . $this->name . "tastes " . $this->flavor . "." . "The record " . $this->species . " " . $this->name . "weighed " . $this->weight . ".";               
    }

}

 $brook_trout = new Trout("Trout", "Delicious", "14 pounds 8 ounces", "Brook")

 echo $trout->getInfo();
?>

What am I doing wrong? Can someone please help?

2 Answers

Kevin Korte
Kevin Korte
28,149 Points
Kevin Korte
Kevin Korte
28,149 Points

So two things.

**I did not check you concatenation real well. Assuming that's okay.

  1. Remember that $name is part of the __construct function, but in the Trout class $name is set to $common_name. So in your getInfo() you can't ask for it's $name, you have to get it's $common_name. Does that make sense?

  2. Earlier you correctly created a variable name $brook_trout and make it a new Trout class. The question specifically asks for information on the Brook Trout, where we added as species, so you would run your getInfo() on the $brook_trout variable, not the $trout variable of the class.

Oğulcan Girginc
Oğulcan Girginc
24,848 Points
Oğulcan Girginc
Oğulcan Girginc
24,848 Points

Thank you very much for explanations Kevin!

Kevin Korte
Kevin Korte
28,149 Points
Kevin Korte
Kevin Korte
28,149 Points

You're welcome. Funny part is I did this lesson myself just a hour or two before you posted questions on the forum, so this stuff was super fresh in my head.

LaVaughn Haynes
LaVaughn Haynes
12,397 Points
LaVaughn Haynes
LaVaughn Haynes
12,397 Points

Your concat is good. You just have a couple of small errors

<?php

//you are missing semicolon at end of next line
 $brook_trout = new Trout("Trout", "Delicious", "14 pounds 8 ounces", "Brook")

//as Kevin was suggesting above you want to use $brook_trout below
 echo $trout->getInfo();

?>