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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by John Locken
John Locken
16,540 Points

Stuck on wordcount.py problem in Python Collections

I feel like I have the correct code for this problem, but I can't get TeamTreehouse to take it. The question is:

Alright, this one might be a bit challenging but you've been doing great so far, so I'm sure you can manage it.

I need you to make a function named word_count. It should accept a single argument which will be a string. The function needs to return a dictionary. The keys in the dictionary will be each of the words in the string, lowercased. The values will be how many times that particular word appears in the string.

Check the comments below for an example.

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(arg):
    words = arg.lower().split(' ')
    dictionary = {}
    for word in words:
        count = words.count(word)
        dictionary[word]=count
    return dictionary
John Locken
John Locken
16,540 Points

When I run this in my Jupyter Notebook, it seems to work. Here is the code I have in my Notebook and here are the results:

arg = 'This is a Test a string'
words = arg.lower().split(' ')
dictionary = {}
for word in words:
    count = words.count(word)
    dictionary[word]=count
print(dictionary)

result: {'this': 1, 'is': 1, 'a': 2, 'test': 1, 'string': 1}

Paul Melos
Paul Melos
3,905 Points
Paul Melos
Paul Melos
3,905 Points

Your code works just fine for me in IDLE. Treehouse's interpreter can be really buggy, you might try restarting the exercise.

1 Answer

Istvan Nonn
Istvan Nonn
2,092 Points
Istvan Nonn
Istvan Nonn
2,092 Points

Try this link, will give you the answer. Once again, Jennifer Nordell saved me.

hint comment