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iOS Functions in Swift Adding Power to Functions Function Parameters

Swift Functions

I am getting this error. Can someone explain it to me? "cannot convert return expression of type 'Bool' to return type 'Int' return remainder"

functions.swift
// Enter your code below
func getRemainder(value a: Int, divisor b: Int) -> Int {
let remainder = a % b == 0
return remainder
}

1 Answer

james south
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james south
Front End Web Development Techdegree Graduate 33,271 Points

your second line a % b == 0 returns a boolean, either true or false. a is either evenly divisible by b or it is not. you then return this boolean, but in your first line where you define the function, you have -> Int, meaning the function returns an integer. that is why that error is being thrown. the return type must be the same as indicated in the function definition.