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Swift weather app Fahrenheit to Celsius?

Hey, Was just wondering whether anyone had solved this so us Aussies can understand it better.

Should probably change the hey to G,Day mate! :) (:

C is Celsius and F is Fahrenheit. You would take the temperature from forecast.io (which is in Fahrenheit) and then substitute into the formula. Something like this:

You make temperature optional with ? in the declaration

add this in the init function:

```    let fahrenheit = currentWeather["temperature"] as Int
temperature = convertToCelsius(fahrenheit)
```

add this function to convert it:

```func convertToCelsius(fahrenheit: Int) -> Int {
return Int(5.0 / 9.0 * (Double(fahrenheit) - 32.0))
}
```

It looks like forecast.io only return the temperature in Fahrenheit. You can convert in the Current struct with this formula:

C = 5/9 * (F-32)

WOW, THANKS SO MUCH FOR HELPING OUT AND GIVING UP SOME OF YOUR TIME!!! MEANS AND HELPS ALOT!!! Though how do you implement this in the code, what is C and F? THANKS AGAIN