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Elliott Mangham
13,086 PointsSwitching the order of variables within a mixin argument
Hi, I thought it'd be simple by just re-ording the $size and $color variables, in addition to the values (10px and red).
But this doesn't seem to resolve it. Please can somebody advice?
<!DOCTYPE html>
<html>
<head>
<title>Sass Basics - Code Challenge</title>
<link rel="stylesheet" type="text/css" href="page-style.css">
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<div class="box"></div>
<div class="red"></div>
<div class="orange"></div>
<div class="yellow"></div>
<div class="green"></div>
</body>
</html>
/* Write your SCSS code below. */
@mixin square($size, $color: black) {
height: $size;
width: $size;
border: 1px solid $color;
}
.box {
@include square(10px, red);
}
2 Answers
Sean T. Unwin
28,690 PointsHi Elliott Mangham.
When using arguments that are not in the order as described in the mixin or function you need to use the name of the variable along with the value. If you're familiar with JavaScript, it's almost like using a function that takes an object with named properties as arguments.
In this case it would be:
.box {
@include square($color: red, $size: 10px);
}
Have fun and happy coding. :)
Elliott Mangham
13,086 PointsSean, thank you