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Java

Mayank Sharma
Mayank Sharma
3,025 Points

Syntax error

I was not able to use System.out.println("..........."); statement for "catch"? Why is it so? Can anybody help?

2 Answers

I see your syntax problem on your println statement. The reason the syntax is incorrect is because of the %s String modifier, you can only use that inside of a printf statement. To print out your message from the getMessage method on a println statement you use + like I did in the example above.

try {
    dispenser.load(400);
    System.out.println("This will never happen");
} catch(IllegalArgumentException iae) {
    System.out.println("Whoa there!!");
    System.out.println("The error was: %s\n", iae.getMessage()); //%s wont work on a println statement.
                                                                //Also, you can still use \n on both a println and printf statement.

    //instead you need to do:
    System.out.println("The error was: " + iae.getMessage());

    //if you wanted to use a printf statement:
    System.out.printf("The error was: %s", iae.getMessage());
}

No problem, let me know if you have any other questions.

Could you please post your code so I can get a better understanding of your problem. Also, if you mean "catch" as in a try-catch block you most certainly can use a println statement like so:

public class TryCatchBlocks {
    public static void main(String[] args) {
        try {
            methodThatThrowsAnException();
        } catch (Exception e) {
            System.out.println("an exception occurred"); //this is redundant if you're using the 'getMessage' method. Unless you want to print out an additional String.
            System.out.println("Yikes: " + e.getMessage()); //this is a much better way of printing a statement inside of a try-catch block.
        }   
    }

    public static void methodThatThrowsAnException()throws Exception {
        throw new Exception("AN EXCEPTION OCCURRED");
    }
 }

This will output:

an exception occurred
Yikes: AN EXCEPTION OCCURRED
Mayank Sharma
Mayank Sharma
3,025 Points

This is the code: public class Example {

public static void main(String[] args) {
    // Your amazing code goes here...
    System.out.println("We are making a new Pez Dispenser.");
    PezDispenser dispenser = new PezDispenser("Donatello");
    System.out.printf("The dispenser character is %s\n", 
                      dispenser.getCharacterName());
  if (dispenser.isEmpty()){
    System.out.println("The dispenser is empty.");
  }
    System.out.println("Loading....");
    dispenser.load();
  if (!dispenser.isEmpty()){
    System.out.println("The dispenser is not empty");
  }
  while(dispenser.dispense()){
System.out.println("Chomp!");

} if (dispenser.isEmpty()){ System.out.println("Ate all the PEZ!"); } dispenser.load(4); dispenser.load(3); while(dispenser.dispense()){ System.out.println("Chomp!"); } try{ dispenser.load(400); System.out.println("This will never happen"); } catch(IllegalArgumentException iae){ System.out.println("Whoa there!!"); System.out.println("The error was: %s\n", iae.getMessage()); }

}

}