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Python

Posted by Arnav Goyal
Arnav Goyal
1,634 Points

Syntax Error

import random

def game():

    secret_num = random.randint(1, 10)

    guess = int(input("Guess a number: ")

    if secret_num == guess_num:
         print ("You got it! My number was {}.".format(secret_num))
    else:
         print("A miss!")


game()

I don't know why the syntax error is being shown.

3 Answers

Myers Carpenter
Myers Carpenter
6,421 Points
Myers Carpenter
Myers Carpenter
6,421 Points 
guess = int(input("Guess a number: ")

count the number of ( then count the number of )

Arnav Goyal
Arnav Goyal
1,634 Points
Arnav Goyal
Arnav Goyal
1,634 Points

Thanks. But that's not the error. The error is being shown in the 'if' statement. 

if secret_num == guess_num:
         print ("You got it! My number was {}.".format(secret_num))
Jonathan Shedd
Jonathan Shedd
1,921 Points

In your code, guess_num was never defined. I think that is the error.

Myers Carpenter
Myers Carpenter
6,421 Points

I put your code in a file and executed it:

  File "tmp.py", line 9
    if secret_num == guess_num:
                              ^
SyntaxError: invalid syntax

The reason you get this syntax error here is that the line before it you open a parenthesis but didn't close it. The python parser is looking for that closing parenthesis but finds a == instead, and errors there.

If you get an error on a line and you can't see anything wrong, try looking to see if it's confused about the line before.

Arnav Goyal
Arnav Goyal
1,634 Points
Arnav Goyal
Arnav Goyal
1,634 Points

Thanks. But I changed 'guess_num' to 'guess'. It still doesn't work. 

if secret_num == guess:
         print ("You got it! My number was {}.".format(secret_num))