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Start your free trialDavid Dunlop
2,844 Pointssyntax error with if else conditional when checking studentOneGPA
this is the question I cant get right
Check if each student has a GPA of 4.0.
If the student has a GPA of 4.0, use the student name variable to replace NAME when displaying the following line:
NAME made the Honor Roll
ELSE If the students GPA is not equal to 4.0, within an else block, use the student name variable to replace NAME AND the student GPA variable to replace STUDENT GPA when displaying the following line:
NAME has a GPA of STUDENT GPA
/// <?php $studentOneName = 'Dave'; $studentOneGPA = 3.8;
$studentTwoName = 'Treasure'; $studentTwoGPA = 4.0;
//Place your code below this comment $NAME = $studentOneName; if ($studentOneGPA = 4.0) { echo "$NAME made the honor roll."; } else { echo "$NAME has a GPA of $STUDENT_GPA."; { $STUDENT_GPA = $studentTwoGPA; $NAME = $studentTwoName; if ($studentTwoGPA = 4.0) { echo "$NAME made the honor roll."; else { echo "$NAME has a GPA of $STUDENT_GPA."; } ?> ///
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
//Place your code below this comment
?>
1 Answer
KRIS NIKOLAISEN
54,971 PointsSome hints:
- Check your brackets, particularly near your else statements
- You don't need to create variables $NAME and $STUDENT_GPA. In fact I think the challenge fails if you don't just use the variables provided.
- Check your comparison operators
- Check case (ex: honor roll). In this challenge the text must be exact.