Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript AJAX Basics (retiring) Programming AJAX Processing JSON Data

Posted by Amaresh Dey
Amaresh Dey
4,859 Points

SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data

var xhr = new XMLHttpRequest(); xhr.onreadystatechange = function(){ if ( xhr.readyState === 4){ var employees = JSON.parse(xhr.responseText); var statusHTML = '<ul class="bulleted">'; for (var i = 0; i<employees.length; i+=1) { if (employees[i].inoffice === true){ statusHTML += '<li class = "in">'; } else { statusHTML += '<li class = "out">'; } statusHTML += employees[i].name; statusHTML += '</li>'; } statusHTML += '</ul>'; document.getElementById("employeeList").innerHTML = statusHTML; } }; xhr.open("GET", "data/employees.js"); xhr.send();

I don't know why this error is showing. Is there any mistake I've done?

john larson
john larson
16,594 Points 
var xhr = new XMLHttpRequest(); 
xhr.onreadystatechange = function(){ 
  if ( xhr.readyState === 4){ 
    var employees = JSON.parse(xhr.responseText); 
    var statusHTML = '<ul class="bulleted">'; 
      for (var i = 0; i<employees.length; i+=1) { 
        if (employees[i].inoffice === true){ 
         statusHTML += '<li class = "in">'; 
       } else {
         statusHTML += '<li class = "out">';
     }  
        statusHTML += employees[i].name; statusHTML += '</li>'; 
   }   
         statusHTML += '</ul>'; document.getElementById("employeeList").innerHTML = statusHTML;
 }
}; 
xhr.open("GET", "data/employees.js"); 
xhr.send();

1 Answer

Evans Owino
Evans Owino
24,888 Points
Evans Owino
Evans Owino
24,888 Points

Hi Amaresh, it seems you have a typo. You wrote "js" instead of "json". The code works once this is sorted.

xhr.open("GET", "data/employees.js");

instead of

xhr.open("GET", "data/employees.json");