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PHP PHP Basics (Retired) PHP Data & Structure PHP Variables

Task 2 of 2 wont work

No matter how many different ways I type it the second task will not display the contents of the $name variable which is Mike.

I've typed it as <?php echo $name ?> <p><?php echo $name ?></p> and <?php echo $name; ?>

nothing seems to work.

index.php
<?php
  $name = "Mike";
?>


<!DOCTYPE html>
<html>
  <body>
    <h1><?php echo $name ?></h1>
  </body>

</html>

4 Answers

Yep, I understand. Sometimes the challenge can be picky about what it will accept. In this case, it will not accept two separate php code blocks. So, the solution looks like this:

<?php

  $name = "Mike";
  echo $name;

?>

Cheers

Hi Doug,

There's no need to create all that html - instead, echo the $name variable right below where it gets assigned the value "Mike".

Cheers

I did in the first attempt, it looked just like this:

<?php echo $name; ?>

The HTML was my last ditch effort in an act of frustration. :/

That did the trick! Thanks!