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PHP Integrating PHP with Databases Filtering Input for Queries Multiple Conditionals

Task 2 of 3

Here's my query: SELECT title FROM Media JOIN People ON Media.media_id = People.people_id LEFT OUTER JOIN Media_People ON Media.media_id = Media_People.media_id AND People.people_id = Media_People.people_id WHERE People.fullname LIKE '%Tolkien';

What is wrong??

2 Answers

Jennifer Nordell
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Jennifer Nordell
Treehouse Teacher

Hi there, George Stathoulias ! First, you need two INNER joins. So you won't need LEFT OUTER JOIN. You have some combination here where you're trying to do the media_id = people_id from different tables. But the media_id in one table should be equal to the media_id recorded in the other table. The same thing goes for media_id. The Media_People table is just a table with two columns. Each column has a list of integers. One column is for the people_id and the other column is for the media_id. Assuming the person was "Tom Hanks" and their people_id was 3, I'm expecting that "Media_People" table to have quite a number of entries where the people_id is 3 and each movie he's been in is recorded with its media_id which then looks up the title of the movie in the Media table.

This was my solution:

SELECT title FROM Media
JOIN Media_People ON Media_People.media_id = Media.media_id
JOIN People ON People.people_id = Media_People.people_id
WHERE fullname LIKE '%Tolkien';

Note that the media_id in the joining table matches the media_id in the Media table and the person_id in the joining table matches the person_id in the Person table.

Hope this helps! :sparkles:

Thank you Jennifer. You made things clear!