Tbh, I have absolutely no idea how to do this one

Question

It'd be great to have some help, and to be given some tips for the future! :)

even.py

import random

start = 5

while start == True:
    number = random.randint(1, 99)
    if number == even_odd:
        print("{} is even".format(number))
    else:
        print("{} is odd".format(number))

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

Answer 1 · 2018-01-10T06:21:20Z

January 10, 2018 6:21am

Hey!

So you are very close to a right answer! The first thing I would like to point out is that in challenge 3, it explicitly says near the end: "Finally, decrement start by 1." You need to subtract 1 from start at the end of loop in your while statement.

The second issue is the statement "if number == even_odd:".

Take a close look at this. You are asking if the number is equal to a function, not the return value of the function. This is because you are not actually calling the function.

IE:

>>> def even_odd(num):
...   return not num % 2

>>> print ( even_odd )
<function even_odd at 0x1091092a8>
>>> print ( even_odd(10) )
True

The other issue with this if statement is that it returns a boolean of True or False (True for even, False for odd). You do not want to compare the number to this value.

The last issue is that you are calling the even_odd() function before you declare it. You will want to move the while loop after you declare the function or else Python will say that it has no idea what function you are talking about because it hasn't gotten that far in the script yet.

Hopefully this helps you out some! If not, feel free to leave a comment below and I'll try my best to further explain any issues or someone else may be able to come along and explain it better than I can :)

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charlesmonaghan

charlesmonaghan

Tbh, I have absolutely no idea how to do this one

1 Answer

Logan R

Logan R