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# Teachers stats step 1

I started several attempts but I am still very noob in python, any pointers with included logic would be very helpful. Yours Truly: Pipemaster P

teachers.py
```# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
#  'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
dic = {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
'Kenneth Love': ['Python Basics', 'Python Collections']}
def num_teachers(dic):
counts = []
for key in dic:
counts.append(len(dic[key]))
return counts
```

MOD

You're slightly off track in solving the task: "`The num_teachers function should return an integer for how many teachers are in the dict.`"

Let's get your code back on track. First there are some indentation issues. The `for` loop needs to be indented:

```def num_teachers(dic):
counts = []
for key in dic: #for each teacher
# append the length of the dict value
counts.append(len(dic[key]))
return counts # return list of values
```

In the comments, you can see you are returning a list of values representing the number of courses each teach has.

Instead, you want to count the number of teachers themselves not their courses, and also want to return the sum of the values. These are corrected below:

```def num_teachers(dic):
counts = []
for key in dic:
return sum(counts) # return sum
```

This is basically just counting the number of dict keys. This can be done without a `for` loop.

```def num_teachers(dic):
counts = len(dic.keys())
return counts
```

Since the length of a dict is the same as the number of keys this can be reduced to:

```    counts = len(dic)
```

The most reduced option did not work for me as an answer.