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Python Python Collections (Retired) Dictionaries Teacher Stats

Andrew K
Andrew K
13,774 Points
Posted by Andrew K
Andrew K
13,774 Points

teachers.py 3/3 Can't figure out why I'm getting either "Bummer! Where's stats()" or "Task One is no longer passing"

Hello! I've been stumped on this for a bit and was hoping for a bit of help. Here's my code, but everything was going smoothly until the last function:

def most_classes(teachers):
  high_classes = 0
  high_teacher = ''
  for teacher in teachers:
    if len(teachers[teacher]) > high_classes:
      high_classes += 1
      high_teacher = teacher
    return high_teacher

def num_teachers(teach_dict):
  teach_count = 0
  for name in teach_dict:
    teach_count += 1
  return teach_count

def stats(teachers):
  total_stats = []
  for teacher in teachers:
    teach_stats = []
    teach_stats.append(teacher)
    teach_stats.append(len(teacher[classes]))
    total_stats.append(teach_stats)
  return total_stats

Any help is greatly appreciated!

3 Answers

Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Hi Andrew,

Your first function is not passing for me. You have high_classes += 1 and it should be high_classes = len(teachers[teacher])

You don't want to increment that variable. You want to set it equal to the number of courses for that teacher.

For your stats function you are referencing a variable classes that doesn't exist. teach_stats.append(len(teacher[classes]))

You want to append the number of courses for the current teacher you're on. teach_stats.append(len(teachers[teacher]))

def stats(teachers):
  total_stats = []
  for teacher in teachers:
    teach_stats = []
    teach_stats.append(teacher)
    teach_stats.append(len(teachers[teacher]))
    total_stats.append(teach_stats)
  return total_stats

You could also write that function like this and get rid of the intermediate teach_stats variable:

def stats(teachers):
  total_stats = []
  for teacher in teachers:
    total_stats.append( [teacher, len(teachers[teacher])] )
  return total_stats
Jason Anello
Jason Anello
Courses Plus Student 94,610 Points

Also, it's possible to get the length of a dictionary similar to how you do for a list. So really you could simplify the num_teachers function as well. Rather than iterate over each key in the dictionary and increment a counter you could get the length of the dictionary instead.

def num_teachers(teach_dict):
  return len(teach_dict)
Andrew K
Andrew K
13,774 Points
Andrew K
Andrew K
13,774 Points

Jason,

Thank you so much for your response. It cleared up a lot, but it also showed me that some things I was doing are redundant! I rewrote it after reading your post, and it all passed. One odd thing, and I don't know if others experience this, but sometimes when my code returns "Task One no longer passed" (as in this instance, after redoing the code) if I just resubmit once or twice... it passes. Weird.

Thanks again, Jason!

Radha Bhambwani
Radha Bhambwani
10,182 Points
Radha Bhambwani
Radha Bhambwani
10,182 Points

Andrew I was also getting that, "Task one is no longer passed" as well, not sure why either.

As to this post, the activity taught me a lot also however I keep getting a syntax error problem in my code:

def stats(teachers):

  teacher_list = []

  for teacher in teachers:

    teacher_list.append([teacher, len(teachers(teacher))

  return teacher_list

Specifically it points to the return, which I'm not sure about (This is for part 3 btw)

Andrew K
Andrew K
13,774 Points
Andrew K
Andrew K
13,774 Points

Hi Radha, Your function looks fine, but I think you are just losing track of your brackets and parentheses. Your append line should look like this:

teacher_list.append([teacher, len(teachers[teacher])])

So you're missing one square bracket (to close off your list) and when you access the key (teacher), that should be in square brackets, not parentheses.

Hope that helps!