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Start your free trialMatthew Byrne
1,920 Pointsteachers.py() part 2
I ran this on workspaces and it worked perfectly. It doesn't pass the test however. Any suggestions?
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(dic):
for teachers in dic:
teacher_count = len(dic.keys())
return teacher_count
def num_courses(dic):
new_list = []
for teachers in dic:
value_count = dic.values()
new_list.extend(value_count)
list_len = len(new_list)
return(list_len)
1 Answer
Steven Parker
231,269 PointsWhen you say it "worked perfectly", you may have misunderstood the objective. The challenge says, "The function should return the total number of courses for all of the teachers." Note that's "all" and not "each".
So just as "num_teachers" returned a total number, "num_courses" should return a single value with a grand total instead of a list.