Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialDavid Wright
4,437 PointsTeachers.py Task 4 of 4 - Please help me get to Tuples!
I'm not sure why it is only showing 5 values rather than 18
# The dictionary will be something like:
# {'Jason Seifer': ['Ruby Foundations', 'Ruby on Rails Forms', 'Technology Foundations'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Often, it's a good idea to hold onto a max_count variable.
# Update it when you find a teacher with more classes than
# the current count. Better hold onto the teacher name somewhere
# too!
#
# Your code goes below here.
def most_classes(teacher_dict):
max_count = 0
for key, value in teacher_dict.items():
if len(value) > max_count:
max_count = len(value)
max_teacher = key
return max_teacher
def num_teachers(teacher_dict):
teacher_count = 0
for teacher in teacher_dict:
teacher_count += 1
return teacher_count
def stats(teacher_dict):
teacher_list = []
for teacher in teacher_dict:
teacher_list.append([teacher, len(teacher_dict[teacher])])
return teacher_list
def courses(teacher_dict):
course_list = []
for courses in teacher_dict.values():
course_list.append(courses)
return course_list
1 Answer
Steven Parker
231,272 PointsThe error message is somewhat misleading. What you actually returned was not 5 courses, but 5 lists of courses.
All you need now is to iterate through the courses in each list and append each individual course to your master list:
def courses(teacher_dict):
course_list = []
for courses in teacher_dict.values():
for course in courses:
course_list.append(course)
return course_list
OR you could just concatenate the lists of courses:
def courses(teacher_dict):
course_list = []
for courses in teacher_dict.values():
course_list += courses
return course_list
And I recently learned of a way to do the first method in a single line (though this is beyond what is covered in this particular course):
def courses(teacher_dict):
return [course for courses in teacher_dict.values() for course in courses]
David Wright
4,437 PointsDavid Wright
4,437 PointsThanks a million, Steven! Also, thank you for giving me a general rundown of what I needed to re-examine (to start your feedback) before giving me corrected code! It allowed me to come to this on my own without looking at your code.
Also, thank you for showing me multiple methods for solving and for the super concise one you recently learned!
David Wright
4,437 PointsDavid Wright
4,437 PointsI still need to learn Markdown.. sorry
Steven Parker
231,272 PointsSteven Parker
231,272 PointsI normally avoid giving spoilers at all, but you were so close already plus it was an easy way to show the multiple approaches.
The trick to blockquotes in markdown is to skip a line, then put three accents ("backticks") on separate lines, and then your code in between. If possible, specify the language after the first set of accents, like this:
```py
def noop(something):
"""Do nothing here"""
return something
```
and that produces this:
David Wright
4,437 PointsDavid Wright
4,437 PointsThanks for the Markdown help, Steven! That will help a lot, both on here, and when I start using Github!