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Python Technical Interview Prep: Python Basics Basic Python Splitsville

Noor Hafiza Binti Ibrahim
Noor Hafiza Binti Ibrahim
11,712 Points

Technical Interview Prep: Python Basics - Splitsville

Help, i can’t return the correct keys and values in the dictionary. Any suggestions?

split.py
def splitsville(address):
    keys = "street", "city", "state", "zip_code"
    text = "100 E Main St, Anywhereville, Oregon, 22222"
    value = text.split(", ")
    address = dict(zip(keys, value))
    return address

4 Answers

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,423 Points

Hey Noor Hafiza Binti Ibrahim, you are SO close.

  • The string split needs to be on the parameter address instead of the test value text
  • The built-in zip returns an iterable. To unroll it as an argument to dict(), wrap the zip in a list()

Post back if you need more help. Good luck!!

Mohammed Saleh
seal-mask
.a{fill-rule:evenodd;}techdegree
Mohammed Saleh
Python Development Techdegree Student 2,989 Points
def splitsville(address):

    keys = "street", "city", "state", "zip_code"
    text = address.split()
    dictionary = dict(zip(keys, text))

    return dictionary


splitsville("100 E Main St, Anywhereville, Oregon, 22222")

why it is not going through !!

Chris Freeman
Chris Freeman
Treehouse Moderator 68,423 Points

Hey Mohammed Saleh, your spot on, except your choice of split parameters. The address elements are separated by a comma-space “, “. Change the split parameter and pass the challenge!

Post back if you need more help. Good luck!!!