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JavaScript JavaScript Foundations Arrays Methods: Part 2

Gavin Murphy
Gavin Murphy
10,004 Points

The approach to this challenge was not really clear in the previous video. Where would you use the .length method in thi

What is the answer. thanks

index.html
<!DOCTYPE html>
<html lang="en">
  <head>
    <title> JavaScript Foundations: Arrays</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Arrays: Methods Part 1</h2>
    <script>
      var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
      var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
      saying1.reverse();
      saying2.sort(function a.length, b.length){
        return a - b;
      }
    </script>
  </body>
</html>

1 Answer

Hi Gavin,

You weren't far off with what you have. Just swap the a.length and b.length that you're passing in with those in your return and that should do it.

Thanks

-Rich

Gavin Murphy
Gavin Murphy
10,004 Points

Cheers man, I actually got it just now, lack of parenthsis as well as the .length in the wrong place... Thanks for the quick reply

No problem :)