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JavaScript AJAX Basics (retiring) AJAX Concepts A Simple AJAX Example

Posted by meghana Joshi
meghana Joshi
4,596 Points

The code is not working , I checked the syntax 

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <link href='//fonts.googleapis.com/css?family=Varela+Round' rel='stylesheet' type='text/css'>
  <link rel="stylesheet" href="css/main.css">
  <title>AJAX with JavaScript</title>
  <script>
    var xhr = new XMLHttpRequest();
    xhr.onreadystatechange = function(){
      if(xhr.readyState ===4){
        documet.getElementById("ajax").innerHTML = xhr.responseText;
      }
    };
    xhr.open('GET', 'sidebar.html');
    xhr.send();

  </script>
</head>
<body>
  <div class="grid-container centered">
    <div class="grid-100">
      <div class="contained">
        <div class="grid-100">
          <div class="heading">
            <h1>Bring on the AJAX</h1>
          </div>
          <div id="ajax">

          </div>
        </div>
      </div>
    </div>
  </div>
</body>
</html>

3 Answers

Emmanuel C
Emmanuel C
10,636 Points
Emmanuel C
Emmanuel C
10,636 Points

Hey meghana,

There is actually a syntax error, of document being misspelled in your if statement. But is there a sidebar.html? Since I dont have it, its coming back null then trying to put that null in the innerHTML of the element with id="ajax".

An awesome way to debug js this to open it open in your browser. I literally copied and pasted your code into a blank text file then renamed it to index.html and opended it up in my browser. Then i open the devTools with F12 and it showed me all the errors. Its very useful fixing bugs.

meghana Joshi
meghana Joshi
4,596 Points
meghana Joshi
meghana Joshi
4,596 Points

Thanks

Roger Hwang
Roger Hwang
3,851 Points
Roger Hwang
Roger Hwang
3,851 Points

I realized my code wasn't working since I was typing notes in Microsoft Word and copied code from there to Workspace. Unfortunately, the quote marks aren't the same.