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JavaScript JavaScript Basics (Retired) Making Decisions with Conditional Statements Using Comparison Operators

The else clause is not being recognized with the alert command

I followed the instructions and now the challenge is telling me that the else clause alert is not there, when I clearly put it there.

I even put the curly brackets around the else clause to see if that was the problem but it made things worse so I left them out. Is there something I'm missing to solve this problem. If there is, could you explain what I did wrong so I can understand?

Thank you kindly!

var a = 10;
var b = 20;
var c = 30;

if ('a > b')
  alert ('a is greater than b'); 

else ('a < b')
 alert ('a is not greater than b');
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
<script src="script.js"></script>

2 Answers

Steven Parker
Steven Parker
221,963 Points

The message may be a bit misleading, the actual issue is that an "else" does not take a comparison expression. It doesn't need one since it handles anything not covered by the "if".

Yeah that's what I thought but if I remove the comparison expression, I get this error message:

"I don't see the message 'a is NOT greater than b'. Are you sure you wrote the conditional statement correctly?"

Steven Parker
Steven Parker
221,963 Points

I missed it the first time, but you don't want to put quotes around your conditional expression. That would make it a string literal, which by the fact that it's not empty is always "truthy".

Thank you Steven, that helped when I removed the quotes. I'm still having a hard time determining when to or not to put quotes in something. Thanks for your help!

Steven Parker
Steven Parker
221,963 Points

This hint might help: Generally, you'll never put quotes around a variable name, or an expression that uses an operator for calculating or comparing anything. Putting quotes around something makes a string literal, which doesn't represent anything except for the actual letters and symbols in the quotes. For example:

console.log("23 + 17");  // the console will show:  23 + 17
console.log(23 + 17);    // the console will show:  40