the error message is "wrong number of prints"

Question

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start < 5:
    num = random.randint(1,99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

even.py

import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start < 5:
    num = random.randint(1,99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

Ken Alger · Answer

Emmanuel;
Take a look at your while statement logic as it relates to the start value. When the program first runs will it get into the while loop?
For the sake of argument, let's say that it does, will it ever end?
Post back if you're still stuck.
Ken

Emmanuel Owolabi

Emmanuel Owolabi

the error message is "wrong number of prints"

1 Answer

Ken Alger

Ken Alger

Emmanuel Owolabi

Emmanuel Owolabi