Python Python Basics (2015) Letter Game App Even or Odd Loop

the error message is "wrong number of prints"

import random def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2 start = 5 while start < 5: num = random.randint(1,99) if even_odd(num): print("{} is even".format(num)) else: print("{} is odd".format(num)) start -= 1

even.py
import random
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
start = 5
while start < 5:
    num = random.randint(1,99)
    if even_odd(num):
        print("{} is even".format(num))
    else:
        print("{} is odd".format(num))
    start -= 1

1 Answer

Ken Alger
STAFF
Ken Alger
Treehouse Teacher

Emmanuel;

Take a look at your while statement logic as it relates to the start value. When the program first runs will it get into the while loop?

For the sake of argument, let's say that it does, will it ever end?

Post back if you're still stuck.

Ken

Absolutely, i found it even before your post but thanks for the response. It should be " while start : "