The error message just says "Bummer ! Try again!

Question

def add(arg1,arg2):
    try:
        float(arg1)
        float(arg2)
        except ValueError:
            return none
        else:
             return float(arg1) + float(arg2)
not sure why this code is wrong
```trial.py
def add(arg1,arg2):
    try:
        float(arg1)
        float(arg2)
        except ValueError:
            return none
        else:
             return float(arg1) + float(arg2)
```

carlos florez · Answer

Your try block should suffice without the need for an else statement. Try returns the addition between both arguments, shall we pass something other than an "integer" or number as arguments a ValueError is "raised", in this case we are already using the exception as an else statement, "if ValueError is presented do this instead", which is to return None
python
def add(x, y):
    try:
        return float(x) + float(y)
    except ValueError:
        return None

ujjwal shankar · Answer

hi Manish , 
Thanks for response , yes i figured that..
Cheers, 
Ujjwal

Manish Giri · Answer

Your indentation is wrong, except and else seem to be inside the try block, whereas they should be on the same level -

try:
    # code
except:
    # code
else:
    # code

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ujjwal shankar

ujjwal shankar

The error message just says "Bummer ! Try again!

3 Answers

Manish Giri

Manish Giri

ujjwal shankar

ujjwal shankar

carlos florez

carlos florez