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# The 'max' function isn't rendering a number

I'm trying to figure out why my function isn't rendering

x = max(2, 5);

function max(a, b) { if (b > a) { return max; } else { return false; } };

Thanks,

John

script.js
```x = max(2, 5);

function max(a, b) {
if (b > a) {
return max;
} else {
return false;
}
};
```

```var x = max(2, 5);

function max(a, b) {
if (b > a) {
return b;
} else {
return a;
}
};
```

this returns the maximum value out of a and b, your method doesnt work because it was returning the function itself if b > a and false otherwise

```function max(a, b) {
return (a > b) ? a : b;
}

var x = max(2, 5);
```

don't think a beginner should use the conditional (ternary) operator yet, but it is the shortest solution

Oh ye, you are right..

then it should be as you post:

```function max(a, b) {
if (a > b) return a;
else return b;
}
```