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John White
7,101 PointsThe 'max' function isn't rendering a number
I'm trying to figure out why my function isn't rendering
x = max(2, 5);
function max(a, b) { if (b > a) { return max; } else { return false; } };
Thanks,
John
x = max(2, 5);
function max(a, b) {
if (b > a) {
return max;
} else {
return false;
}
};
2 Answers

doesitmatter
12,884 Pointsvar x = max(2, 5);
function max(a, b) {
if (b > a) {
return b;
} else {
return a;
}
};
this returns the maximum value out of a and b, your method doesnt work because it was returning the function itself if b > a and false otherwise

Ivan Bagaric
Courses Plus Student 12,356 Pointsfunction max(a, b) {
return (a > b) ? a : b;
}
var x = max(2, 5);

doesitmatter
12,884 Pointsdon't think a beginner should use the conditional (ternary) operator yet, but it is the shortest solution

Ivan Bagaric
Courses Plus Student 12,356 PointsOh ye, you are right..
then it should be as you post:
function max(a, b) {
if (a > b) return a;
else return b;
}