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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Create a max() Function

The 'max' function isn't rendering a number

I'm trying to figure out why my function isn't rendering

x = max(2, 5);

function max(a, b) { if (b > a) { return max; } else { return false; } };

Thanks,

John

script.js
x = max(2, 5);

function max(a, b) {
  if (b > a) {
    return max;
  } else {
    return false;
  }
};

2 Answers

var x = max(2, 5);

function max(a, b) {
  if (b > a) {
    return b;
  } else {
    return a;
  }
};

this returns the maximum value out of a and b, your method doesnt work because it was returning the function itself if b > a and false otherwise

function max(a, b) {
  return (a > b) ? a : b;
}

var x = max(2, 5);

don't think a beginner should use the conditional (ternary) operator yet, but it is the shortest solution

Oh ye, you are right..

then it should be as you post:

function max(a, b) {
   if (a > b) return a;
   else return b;
}