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JavaScript jQuery Basics (2014) Creating a Simple Drawing Application Perform: Part 3

Sonja Tomcic
Sonja Tomcic
6,590 Points
Posted by Sonja Tomcic
Sonja Tomcic
6,590 Points

The new color circle doesn't apear

when i click on add color, there is no new circle, just empty space and under it it says $newColor

//problem: no user interaction causes no change to application
//solution: when user interacts cause changes appropriately
var color=$(".selected").css("background-color");

//when clicking on control list items
$(".controls").on("click", "li", function(){
  //deselect sibling elements
  $(this).siblings().removeClass("selected");
  //select clicked element
  $(this).addClass("selected");
  //cache current color
  color=$(this).css("background-color");
});


//when new color is pressed
$("#revealColorSelect").click(function(){
  //show color select or hide the color select
  changeColor();
  $("#colorSelect").toggle();
});


//update the new color span
function changeColor(){
  var r=$("#red").val();
  var g=$("#green").val();
  var b=$("#blue").val();
  $("#newColor").css("background-color", "rgb(" + r + ", " + g + ", " + b + ")");   
   }                   

//when color sliders change
 $("input[type=range]").change(changeColor);

//when add color is pressed
$("#addNewColor").click(function(){
  //append the color to the controls ul
  var $newColor = $("<li></li>");
  $newColor.css("background-color", $("#newColor").css("background-color"));
  $(".controls ul").append("$newColor");

  //select the new color
  $newColor.click();
});

//on mouse events on the canvas
  //draw lines
jag
jag
18,266 Points
jag
jag
18,266 Points

You can do 3 ( ` ) followed by js for a js code block.

1 Answer

jag
jag
18,266 Points
jag
jag
18,266 Points 
// This is causing the issue, you are adding a string instead of the variable.
$(".controls ul").append("$newColor");


// This will add new color
$(".controls ul").append($newColor);

Since you saved $newColor as a variable it needs to be used as a variable or else you will see $newColor as a string.

Sonja Tomcic
Sonja Tomcic
6,590 Points
Sonja Tomcic
Sonja Tomcic
6,590 Points

thank you, I haven't seen that