The queryset() method needs to call filter() on its 'queryset' argument.

Question

I bivalve my code is right but don't working , were is my mistake ?

courses/admin.py

from django.contrib import admin

from . import models

class TextInline(admin.StackedInline):
    model = models.Text

class QuizInline(admin.StackedInline):
    model = models.Quiz

class AnswerInline(admin.StackedInline):
    model = models.Answer

class TopicListFilter(admin.SimpleListFilter):
    title = 'topic'
    parameter_name =  'topic'

    def lookups(self, request, model_admin):
        return (
            ('Python', 'Python'), 
            ('Ruby', 'Ruby'),
            ('Java', 'Java'),
        )

    def queryset(self, request, queryset):
        if self.value() == 'Python':
            return queryset.filter(title__contains='Python')
        if self.value() == 'Ruby':
            return queryset.filter(title__contains='Ruby')
        if self.value() == 'Java':
            return queryset.filter(title__contains='Java')


class CourseAdmin(admin.ModelAdmin):
    inlines = [TextInline, QuizInline]

    list_filter = ['created_at', 'is_live']

admin.site.register(models.Course, CourseAdmin)

Answer 1 · 2017-03-01T04:39:17Z

March 1, 2017 4:39am

This is very close. The strings need to be in lower case to pass the challenge:

    def queryset(self, request, queryset): 
        if self.value() ==  'python': 
            return queryset.filter(title__contains='python')
        if self.value() ==  'ruby': 
            return queryset.filter(title__contains='ruby')
        if self.value() ==  'java': 
            return queryset.filter(title__contains='java')

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Thiago Oliveria

Thiago Oliveria

The queryset() method needs to call filter() on its 'queryset' argument.

1 Answer

Chris Freeman

Chris Freeman