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JavaScript JavaScript Loops, Arrays and Objects Tracking Multiple Items with Arrays Using Array Indices

The script.js file contains an array of string values -- the names of players in a game. Let's practice using array

The script.js file contains an array of string values -- the names of players in a game. Let's practice using array indices to access individual names in the array. Log the first name of the array using the console.log() method.

script.js
var players = ['Jim', 'Shawna', 'Andrew', 'Lora', 'Aimee', 'Nick'];
console.log('Jim'[]);
index.html
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

3 Answers

Tom Nguyen
Tom Nguyen
33,501 Points

solution:

script.js
const players = ['Toni', 'Anwar', 'Mali', 'Carlos', 'Cormac', 'Sariah'];
console.log(players[0]);
console.log(players[5]);
Sean T. Unwin
Sean T. Unwin
28,690 Points

The goal is to get the first value of the Array. The Array is called players and the value we are seeking is 'Jim'. Now, the value is mostly irrelevant because we only care about the first item in the Array, it just happens to be 'Jim'.

As KWAME ADJEI mentioned, Arrays use zero-based indexing. Arrays have Key/Value pairs, similar to an Object. The difference being is that Arrays cannot have named Keys so they are numbered and start at zero (0).

So the way to get that first Array item is to reference the variable the Array is named, players, then use bracket notation to get the first item, which is Key 0. This would look like: players[0]. Simply place that inside the brackets of console.log().

KWAME ADJEI
KWAME ADJEI
4,627 Points

I'm not sure of the question but arrays are 0 based so the first index of the array is 0.

Try console.log('Jim'[0]);