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Nicola Sansom
1,306 PointsThere is a compiler error. Please click on preview to view your syntax errors!
I entered in “intAsString = randomNumber + “”; but I am getting a “There is a compiler error. Please click on preview to view your syntax errors! “ I checked the preview but do not understand what I have done wrong any ideas?
Random randomGenerator = new Random();
Int randomNumber = randomGenerator.nextInt(10);
intAsString = randomNumber + "";
3 Answers
Steve Hunter
57,712 PointsThat's a new error caused because you've not declared intAsString to be a String. Add the word String before it:
String intAsString = randomNumber + "";
That should sort it for you.
Steve.
Steve Hunter
57,712 PointsHi Nicola,
You should change Int to int as you declare the randomNumber variable - that one letter could be causing the problems you're experiencing!
int randomNumber = randomGenerator.nextInt(10);
Steve.
Nicola Sansom
1,306 PointsHi I just tried changing it to a lowercase letter but still having trouble this is what the preview screen says
JavaTester.java:67: error: cannot find symbol intAsString = randomNumber + ""; ^ symbol: variable intAsString location: class JavaTester JavaTester.java:111: error: cannot find symbol if (!(intAsString instanceof String)) { ^ symbol: variable intAsString location: class JavaTester JavaTester.java:115: error: cannot find symbol if (!intAsString.equals(Integer.toString(randomNumber))) { ^ symbol: variable intAsString location: class JavaTester 3 errors
raajiabraham
2,609 PointsRandom randomGenerator= new Random();
int randomNumber = randomGenerator.nextInt(10);
String intAsString = randomNumber +"";