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Android Build a Simple Android App (2014) Basic Android Programming Using the Random Class

Posted by Nicola Sansom
Nicola Sansom
1,306 Points

There is a compiler error. Please click on preview to view your syntax errors!

I entered in “intAsString = randomNumber + “”; but I am getting a “There is a compiler error. Please click on preview to view your syntax errors! “ I checked the preview but do not understand what I have done wrong any ideas?

RandomTest.java 
Random randomGenerator = new Random();
Int randomNumber = randomGenerator.nextInt(10);
intAsString = randomNumber + "";

3 Answers

Steve Hunter
Steve Hunter
57,682 Points

That's a new error caused because you've not declared intAsString to be a String. Add the word String before it:

String intAsString = randomNumber + "";

That should sort it for you.

Steve.

Steve Hunter
Steve Hunter
57,682 Points
Steve Hunter
Steve Hunter
57,682 Points

Hi Nicola,

You should change Int to int as you declare the randomNumber variable - that one letter could be causing the problems you're experiencing! 

int randomNumber = randomGenerator.nextInt(10);

Steve.

Nicola Sansom
Nicola Sansom
1,306 Points

Hi I just tried changing it to a lowercase letter but still having trouble this is what the preview screen says

JavaTester.java:67: error: cannot find symbol intAsString = randomNumber + ""; ^ symbol: variable intAsString location: class JavaTester JavaTester.java:111: error: cannot find symbol if (!(intAsString instanceof String)) { ^ symbol: variable intAsString location: class JavaTester JavaTester.java:115: error: cannot find symbol if (!intAsString.equals(Integer.toString(randomNumber))) { ^ symbol: variable intAsString location: class JavaTester 3 errors

raajiabraham
raajiabraham
2,609 Points
raajiabraham
raajiabraham
2,609 Points 
Random randomGenerator= new Random();
int randomNumber = randomGenerator.nextInt(10);
String intAsString = randomNumber +"";