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JavaScript JavaScript Loops, Arrays and Objects Tracking Multiple Items with Arrays Using For Loops with Arrays

Anupam Kumar
Anupam Kumar
940 Points

These two same loops provides different output pattern on console could not understand why?

var name = ['Anupam','AnuPriya','Apoorva']; /* loop 01*/ for( var i=0;i<name.length;i+=1) { console.log(name[i]);

} /* loop 02*/ var orderQueue = ['Anupam','AnuPriya','Apoorva']; for( var i=0;i<orderQueue.length;i+=1) { console.log(orderQueue[i]); }

3 Answers

Dom Farnham
Dom Farnham
19,421 Points

Can you share the output? Do you have both loops in the same js file? If so, instead of using i in the 2nd loop, replace i with j.

Let me know how you get on. Hope this helps. :-)

Anupam Kumar
Anupam Kumar
940 Points

Hey Dom, Please find below the outputs , I even tried with changing the variables with j, but it gave same result on console. I got desired result on web, but curious to know why console gives these different outputs for same loops /* loop 01*/ var name = ['Anupam','AnuPriya','Apoorva']; for( var i=0;i<name.length;i+=1) { console.log(name[i]); } Output A n u p a m , A n u P r i y a , A p 2o r v a

/* loop 02*/ var orderQueue = ['Anupam','AnuPriya','Apoorva']; for( var i=0;i<orderQueue.length;i+=1) { console.log(orderQueue[i]); } Anupam AnuPriya Apoorva undefined

Dom Farnham
Dom Farnham
19,421 Points

I don't think it is a good idea to call your array 'name'. Can you replace name with something else, like names, and see if the output from console.log is different.

Seth Kroger
Seth Kroger
56,407 Points

The trouble is name ends up being a single string instead of an array. The window object which supplies bunch of predefined global variables already has a name property which is an empty string. Because name already exists as a string, it will try to coerce the value you try to assign to a string.

This problem occurs when using var but not the new let/const keywords

Anupam Kumar
Anupam Kumar
940 Points

Thanks Seth, for helping me out; It worked