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mamadou diene
Python Web Development Techdegree Student 1,971 PointsThis challenge is similar to an earlier one. Remember, though, I want you to practice! You'll probably want to use try a
Im stuck on this challenge
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def square(argum):
try:
if argum = int:
return argum*argum
except ValueError:
return len(argum)* argum
3 Answers
Chris Freeman
Treehouse Moderator 68,457 PointsYou have the right idea. To check is something is an int you can use isinstance(argum, int) to test object type. (Taught in later lesson)
Since you have a try block, you can also remove the if and just "go for it" by using argum = int(argum)
Remember to align the except with the try
Post back if you need more help. Good luck!!!
mamadou diene
Python Web Development Techdegree Student 1,971 Pointsthat is after i remove the "if", and correct the rest of the line like you said.
mamadou diene
Python Web Development Techdegree Student 1,971 PointsIt worked!!!!! Thank you!!!!
mamadou diene
Python Web Development Techdegree Student 1,971 Pointsmamadou diene
Python Web Development Techdegree Student 1,971 PointsThis is what i am getting now: SyntaxError: argum = int(argum):
Chris Freeman
Treehouse Moderator 68,457 PointsChris Freeman
Treehouse Moderator 68,457 PointsThe colon should be removed